## Can you see what this is ?

Show us your models and discuss model-making techniques. Paper? Wood? Single vs double tabs? etc.
Peter Kane
Posts: 90
Joined: Sun Oct 25, 2009 11:50 am
Location: S.E England

### Can you see what this is ?

I'm sure that most of you saw it straight away, but it had me fooled until after I'd finished it. It is a compound of ten cubes, but I was convinced at first that it was a compound of only five - until I twigged that there were some corners missing. The ten cubes are aligned with the five incomplete cubes that I thought I was seeing.

I stumbled upon this when playing "the stellation game" with Stella, with a triacontahedron as base. I don't know how long I'd been clicking at this point, but I think it was about 20 or 30 stellations in.

Hope you like it. It looks very good next to a compound of five tetrahedra in the same colours.

Pete K

guy
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Joined: Mon Feb 11, 2008 10:30 am
Location: England
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Ten cubes? Aren't there four of each colour, making 4 x 5 = 20 in all?

Peter Kane
Posts: 90
Joined: Sun Oct 25, 2009 11:50 am
Location: S.E England
guy wrote:Ten cubes? Aren't there four of each colour, making 4 x 5 = 20 in all?
Yes, you are quite right ! How could I possibly think that there were 10 ?
Well spotted, Guy.

Pete K

oxenholme
Posts: 83
Joined: Wed Jan 16, 2008 5:32 am
Location: North West England
This polyhedron is one of 5 that I intend to make.

Its tetrahedral equivalent is a stellation of the regular dodecahedron. I made it last year.

Its octahedral and cubic equivalents are both stellations of the pentagonal icositetrahedron. I made both a year or two ago.

Its icosahedral equivalent is a stellation of the pentagonal hexecontahedron. No doubt it will be a pain to make. I'm not sure whether it can be made using 5 colours.

This one is a stellation of the rhombic triacontahedron - I'm going to make it using 15 colours.